php - Deleting a ROW from MySQL database using MySQLi -

-

i've got delete.php file yes/no buttons call deleterecord.php delete selected row database.

the problem seems i'm not passing variable projectid through deleterecord file.

can please tell me what's wrong?

delete.php

<?php  error_reporting(e_all|e_strict); ini_set('display_errors', true); require('includes/conn.inc.php'); require('includes/functions.inc.php'); $sprojectid = safeint($_get['projectid']); $stmt = $mysqli->prepare("select projectid, projectname, projectimage, languageused, applicationused, description projects projectid = ?"); $stmt->bind_param('i', $sprojectid); $stmt->execute();  $stmt->bind_result($projectid, $projectname, $projectimage, $languageused, $applicationused, $description); $stmt->fetch(); $stmt->close(); ?> <!doctype html> <input name="projectid" type="hidden" value="<?php echo $projectid; ?>"> <html> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8"> <title>delete <?php echo $projectname; ?></title> <link href="styles/cms.css" rel="stylesheet" type="text/css"> </head> <body> <div id="container"> <header> <h1>delete <?php echo $projectname; ?></h1> <?php require('includes/nav.inc.php'); ?><p>hello </p><?php echo "$sprojectid" ?> </header>  <form name="form1" method="get" action="process/deleterecord.php"> <p>are sure wish delete <?php echo $projectname; ?>?</p>    <p>     <input type="submit" name="del" id="del" value="delete">   </p>     </form>  <form name="form2" method="" action="listall.php" id="saveform">     <input type="submit" name="save" id="save" value="save"> </form>  <?php require('includes/footer.inc.php'); ?>  </div>     </body>     </html>

deleterecord.php

<?php error_reporting(e_all|e_strict); ini_set('display_errors', true); require('../includes/conn.inc.php'); require('../includes/functions.inc.php'); // sanitize user variables $sprojectid = safeint($_post['projectid']); // prepare sql $stmt = $mysqli->prepare("delete projects projectid = ?"); $stmt->bind_param('i', $sprojectid); $stmt->execute(); $stmt->close(); //header("location: ../index.php"); // redirect browser exit; // make sure no other code executed ?>

you need write hidden field inside form , change method post.

<form name="form1" method="post" action="process/deleterecord.php">     <p>are sure wish delete <?php echo $projectname; ?>?</p>     <p>         <input name="projectid" type="hidden" value="<?php echo $projectid; ?>">         <input type="submit" name="del" id="del" value="delete">     </p> </form>

as per @volkerk comment below, put input element "within" form element instead of 1 before <html> tag.


Comments

Post a Comment

Popular posts from this blog

Hatching array of circles in AutoCAD using c# -

-
i beginner in autocad plugins .i have created array of circle using following code. now, have hatch circles in array .how that??how hatch circles @ once? moreover, how can return hatch method , use hatch objects.sorry language.thanks in advance. [assembly: commandclass(typeof(beamsection.class1))] namespace beamsection { public class class1 { //class1 obj = new class1(); [commandmethod("beamatsupport")] public void addlightweightpolyline() { // current document , database document acdoc = application.documentmanager.mdiactivedocument; database accurdb = acdoc.database; promptpointresult ppr = acdoc.editor.getpoint("\nselect starting point "); var ucs = acdoc.editor.currentusercoordinatesystem; point3d startingpt = ppr.value.transformby(ucs); list<double> radius = new list<double>(); radius.add(0.5);
Read more

ios - UITEXTFIELD InputView Uipicker not working in swift -

-
hello trying pop uipickerview view programmatically when user clicks on textfield. have tried doesn't doing anything. isn't working. nothing happening when click textfield class userprofiletableviewcontroller: uitableviewcontroller,uitextfielddelegate,uipickerviewdelegate,uipickerviewdatasource { var itempicker: uipickerview! = uipickerview() @iboutlet weak var gendertxtfield: uitextfield! var gender = ["male","female"] override func viewdidload() { super.viewdidload() gendertxtfield.delegate = self itempicker!.delegate = self itempicker!.datasource = self itempicker!.backgroundcolor = uicolor.blackcolor() self.gendertxtfield.inputview = itempicker } func numberofcomponentsinpickerview(pickerview: uipickerview) -> int{ return 1 } // returns # of rows in each component.. func pickerview(pickerview: uipickerview, numberofrowsincomponent component:
Read more

Python Pig Latin Translator -

-
so have been working on @ codecademy.com while trying learn python. don't know if blind , can't see why won't work or what. here's code won't let me use. function print variable if had typed in , print "empty" if didn't type anything. print "welcome english pig latin translator!" original = raw_input("what's name?") if len(original) > 0 print original else print "empty" if len(original) > 0 else the above lines contains syntax errors. try: if len(original) > 0: else: note added colons, ( : ).
Read more