java - JBilling ActiveMQ Scheduler Exception -

-

i trying run jbilling 4.4.1. keep getting following error;

exception in thread "activemq scheduler" java.lang.illegalstateexception: can't overwrite cause java.lang.illegalstateexception: illegal access: web application instance has been stopped already.  not load org.apache.activemq.broker.region.queue$8.  eventual following stack trace caused error thrown debugging purposes attempt terminate thread caused illegal access, , has no functional impact. @ java.lang.throwable.initcause(throwable.java:457) @ org.apache.catalina.loader.webappclassloaderbase.checkstateforclasslo ading(webappclassloaderbase.java:1304) @ org.apache.catalina.loader.webappclassloaderbase.loadclass(webappclas sloaderbase.java:1184) @ org.apache.catalina.loader.webappclassloaderbase.loadclass(webappclas sloaderbase.java:1145) @ org.apache.activemq.broker.region.queue.expiremessages(queue.java:614 @ org.apache.activemq.broker.region.queue.access$100(queue.java:89) @ org.apache.activemq.broker.region.queue$2.run(queue.java:122) @ org.apache.activemq.thread.schedulertimertask.run(schedulertimertask. java:33) @ java.util.timerthread.mainloop(timer.java:555) @ java.util.timerthread.run(timer.java:505) caused by: java.lang.classnotfoundexception @ org.apache.catalina.loader.webappclassloaderbase.checkstateforclasslo  ading(webappclassloaderbase.java:1303)         ... 8 more

how can fix without changing source code? appreciated.

i had same problem, turns out problem in database (postgresql)...

caused by: org.postgresql.util.psqlexception: error: relation     "reseller_entityid_map" not exist   position: 449 @ org.postgresql.core.v3.queryexecutorimpl.receiveerrorresponse(queryexecutorimpl.ja    va:2198)

the "reseller_entityid_map" table missing, once created, restarted tomcat , exception in thread "activemq scheduler" error went away.

you should check following log file:

jbilling-community-4.1.1/bin/logs/jbilling-stacktrace.log

that's found errors:

grep -i psqlexception ./jbilling-community-4.1.1/bin/logs/jbilling-stacktrace.log

Comments

Post a Comment

Popular posts from this blog

Hatching array of circles in AutoCAD using c# -

-
i beginner in autocad plugins .i have created array of circle using following code. now, have hatch circles in array .how that??how hatch circles @ once? moreover, how can return hatch method , use hatch objects.sorry language.thanks in advance. [assembly: commandclass(typeof(beamsection.class1))] namespace beamsection { public class class1 { //class1 obj = new class1(); [commandmethod("beamatsupport")] public void addlightweightpolyline() { // current document , database document acdoc = application.documentmanager.mdiactivedocument; database accurdb = acdoc.database; promptpointresult ppr = acdoc.editor.getpoint("\nselect starting point "); var ucs = acdoc.editor.currentusercoordinatesystem; point3d startingpt = ppr.value.transformby(ucs); list<double> radius = new list<double>(); radius.add(0.5);
Read more

ios - UITEXTFIELD InputView Uipicker not working in swift -

-
hello trying pop uipickerview view programmatically when user clicks on textfield. have tried doesn't doing anything. isn't working. nothing happening when click textfield class userprofiletableviewcontroller: uitableviewcontroller,uitextfielddelegate,uipickerviewdelegate,uipickerviewdatasource { var itempicker: uipickerview! = uipickerview() @iboutlet weak var gendertxtfield: uitextfield! var gender = ["male","female"] override func viewdidload() { super.viewdidload() gendertxtfield.delegate = self itempicker!.delegate = self itempicker!.datasource = self itempicker!.backgroundcolor = uicolor.blackcolor() self.gendertxtfield.inputview = itempicker } func numberofcomponentsinpickerview(pickerview: uipickerview) -> int{ return 1 } // returns # of rows in each component.. func pickerview(pickerview: uipickerview, numberofrowsincomponent component:
Read more

Python Pig Latin Translator -

-
so have been working on @ codecademy.com while trying learn python. don't know if blind , can't see why won't work or what. here's code won't let me use. function print variable if had typed in , print "empty" if didn't type anything. print "welcome english pig latin translator!" original = raw_input("what's name?") if len(original) > 0 print original else print "empty" if len(original) > 0 else the above lines contains syntax errors. try: if len(original) > 0: else: note added colons, ( : ).
Read more