javascript - Why do I need CORS header to request a downloadable link? -

-

i have link allows me download file when click on it. instead of downloading, trying access simple request having cors problems. not have access server side, , therefore have tried far have failed. if understand correctly, suggestions have found far needs me have control on server (i might mistaken, far see server side needs have cors header including domain or have jsonp function envoked).

does mean unable read , parse file downloadable? if yes, how make sense since file public , downloadable when click link. since manually able file, shouldn't possible access code? suggest me solution or give can work on? why code below not work manual click on browser would?

var urlstring = "http://abc.def.com/download?fileid=123&entity_id=123&sid=123"; $.get(urlstring, function(data, status){ alert("data: " + data + "\nstatus: " + status);});

you able download external script manually clicking on link because, well, manually clicked on it! browser knows authorized access url because clicked link pointed it. if bit of javascript accesses url in background, browser can't sure user okay that.

you're thinking "i'm trying download innocent file, why browser not trust me??" let's consider scarier scenario. let's say, instead of trying access http://innocentsite.com/download, javascript trying access https://bankofamerica.com/initiatemoneytransfer?recipient=oe1&amount=10000. without knowing it, user has let send $10,000 since logged in on bankofamerica.com.

now, bank of america (or other respectable bank) doesn't allow $10,000 transfers initiated that. example gets idea across -- dangerous webpages able make http requests other domains. that's why cors headers required.

footnote: if hosting own web server, might setting proxy. have url on website automatically retrieves file other website, , serves on domain. way, can retrieve file without needing other website set cors headers.


Comments

Post a Comment

Popular posts from this blog

Hatching array of circles in AutoCAD using c# -

-
i beginner in autocad plugins .i have created array of circle using following code. now, have hatch circles in array .how that??how hatch circles @ once? moreover, how can return hatch method , use hatch objects.sorry language.thanks in advance. [assembly: commandclass(typeof(beamsection.class1))] namespace beamsection { public class class1 { //class1 obj = new class1(); [commandmethod("beamatsupport")] public void addlightweightpolyline() { // current document , database document acdoc = application.documentmanager.mdiactivedocument; database accurdb = acdoc.database; promptpointresult ppr = acdoc.editor.getpoint("\nselect starting point "); var ucs = acdoc.editor.currentusercoordinatesystem; point3d startingpt = ppr.value.transformby(ucs); list<double> radius = new list<double>(); radius.add(0.5);
Read more

ios - UITEXTFIELD InputView Uipicker not working in swift -

-
hello trying pop uipickerview view programmatically when user clicks on textfield. have tried doesn't doing anything. isn't working. nothing happening when click textfield class userprofiletableviewcontroller: uitableviewcontroller,uitextfielddelegate,uipickerviewdelegate,uipickerviewdatasource { var itempicker: uipickerview! = uipickerview() @iboutlet weak var gendertxtfield: uitextfield! var gender = ["male","female"] override func viewdidload() { super.viewdidload() gendertxtfield.delegate = self itempicker!.delegate = self itempicker!.datasource = self itempicker!.backgroundcolor = uicolor.blackcolor() self.gendertxtfield.inputview = itempicker } func numberofcomponentsinpickerview(pickerview: uipickerview) -> int{ return 1 } // returns # of rows in each component.. func pickerview(pickerview: uipickerview, numberofrowsincomponent component:
Read more

Python Pig Latin Translator -

-
so have been working on @ codecademy.com while trying learn python. don't know if blind , can't see why won't work or what. here's code won't let me use. function print variable if had typed in , print "empty" if didn't type anything. print "welcome english pig latin translator!" original = raw_input("what's name?") if len(original) > 0 print original else print "empty" if len(original) > 0 else the above lines contains syntax errors. try: if len(original) > 0: else: note added colons, ( : ).
Read more