javascript - Traverse an object tree and render a menu tree based on object property condition -

-

hello i'm trying create html menu given object following , wondering if there library can me traverse object, instead of reinventing wheel.

var root = {     category1: {         depth: 0,         categories: {             category1: {                 depth: 1              },             category2: {                 depth: 1,                 products: [1, 2, 3, 4, 5]              },             category3: {                 depth: 1,                 categories: {                     category1: {                         depth: 2,                         products: [1, 2, 3, 4]                     },                     category2: {                         depth: 2,                         products: [1, 2, 3, 4, 5, 6, 7]                     },                     category3: {                         depth: 2                      }                  }             }         }     },     category2: {         depth: 0,         category1: {             depth: 1,         },         category2: {             depth: 1,             products:[1,2,3,4,5]          }     },     category3: {         depth: 0,         category1: {             depth: 1,          },         category2: {             depth: 1,             categories: {                 category1: {                     depth: 2,                     products: [1, 2, 3, 4]                 },                 category2: {                     depth: 2,                     products: [1, 2, 3, 4, 5, 6, 7]                 },                 category3: {                     depth: 2                  }              }          }     },     depth: 0,     category4: {         category1: {             depth: 1,             products:[1,2,3,4,5]         },         category2: {             depth: 1,             categories: {                 category1: {                     depth: 2,                     products: [1, 2, 3, 4]                 },                 category2: {                     depth: 2,                     products: [1, 2]                 },                 category3: {                     depth: 2                  }              }          },         category3: {             depth: 1,          }     }  };

i'm interested in creating menu paths - nodes leaf categories have products other must discarded , not rendered. products can found in level 1 , 2 categories. , each category has depth indicator property indicating level of category.

for example if root category has no leaf level category products not rendered, or depth 1 category no leafs products must not rendered.


Comments

Post a Comment

Popular posts from this blog

Hatching array of circles in AutoCAD using c# -

-
i beginner in autocad plugins .i have created array of circle using following code. now, have hatch circles in array .how that??how hatch circles @ once? moreover, how can return hatch method , use hatch objects.sorry language.thanks in advance. [assembly: commandclass(typeof(beamsection.class1))] namespace beamsection { public class class1 { //class1 obj = new class1(); [commandmethod("beamatsupport")] public void addlightweightpolyline() { // current document , database document acdoc = application.documentmanager.mdiactivedocument; database accurdb = acdoc.database; promptpointresult ppr = acdoc.editor.getpoint("\nselect starting point "); var ucs = acdoc.editor.currentusercoordinatesystem; point3d startingpt = ppr.value.transformby(ucs); list<double> radius = new list<double>(); radius.add(0.5);
Read more

ios - UITEXTFIELD InputView Uipicker not working in swift -

-
hello trying pop uipickerview view programmatically when user clicks on textfield. have tried doesn't doing anything. isn't working. nothing happening when click textfield class userprofiletableviewcontroller: uitableviewcontroller,uitextfielddelegate,uipickerviewdelegate,uipickerviewdatasource { var itempicker: uipickerview! = uipickerview() @iboutlet weak var gendertxtfield: uitextfield! var gender = ["male","female"] override func viewdidload() { super.viewdidload() gendertxtfield.delegate = self itempicker!.delegate = self itempicker!.datasource = self itempicker!.backgroundcolor = uicolor.blackcolor() self.gendertxtfield.inputview = itempicker } func numberofcomponentsinpickerview(pickerview: uipickerview) -> int{ return 1 } // returns # of rows in each component.. func pickerview(pickerview: uipickerview, numberofrowsincomponent component:
Read more

Python Pig Latin Translator -

-
so have been working on @ codecademy.com while trying learn python. don't know if blind , can't see why won't work or what. here's code won't let me use. function print variable if had typed in , print "empty" if didn't type anything. print "welcome english pig latin translator!" original = raw_input("what's name?") if len(original) > 0 print original else print "empty" if len(original) > 0 else the above lines contains syntax errors. try: if len(original) > 0: else: note added colons, ( : ).
Read more