c - What happens to a double variable when %d is used in a printf? -

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so today class teacher give 3 problems , said research @ home.. try hard solution. there no exact article it.

the code is:

#include <stdio.h>  int main(void){     double x = 2.3;      printf("%d\n", x);     printf("%d, x\n");     printf("%d\n", "x"); }

the output is:

  • 1717986918
  • 1717986918, x
  • 4206639

i know need use %lf double. want know problem when used %d. think there memory problem ( 4bit 8bit) or garbage. want know more details problem. assignment. tia

what happens double variable when %d used in printf?

undefined behavior. you're not supposed misuse format specifiers printf.

so working fine program crash sigsegv possibility.

what happen tries treat double int, , depending on how os saves these, garbage print.


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