php - Login app using MySQL database with Android Studio -

-

as title says, i'm trying make first android app simple login feature fetching username , password mysql database i'm getting following error in logcat , app crashes when click on login button

01-27 12:35:11.787 2509-2525/? e/androidruntime: fatal exception: asynctask #2 process: com.example.klm.sql, pid: 2509 java.lang.runtimeexception: error occurred while executing doinbackground() @ android.os.asynctask$3.done(asynctask.java:309) @ java.util.concurrent.futuretask.finishcompletion(futuretask.java:354) @ java.util.concurrent.futuretask.setexception(futuretask.java:223) @ java.util.concurrent.futuretask.run(futuretask.java:242) @ android.os.asynctask$serialexecutor$1.run(asynctask.java:234) @ java.util.concurrent.threadpoolexecutor.runworker(threadpoolexecutor.java:1113) @ java.util.concurrent.threadpoolexecutor$worker.run(threadpoolexecutor.java:588) @ java.lang.thread.run(thread.java:818)  caused by:  java.lang.classcastexception: com.android.okhttp.internal.huc.httpurlconnectionimpl cannot cast javax.net.ssl.httpsurlconnection @ com.example.klm.sql.background.doinbackground(background.java:39) @ com.example.klm.sql.background.doinbackground(background.java:23) @ android.os.asynctask$2.call(asynctask.java:295) @ java.util.concurrent.futuretask.run(futuretask.java:237) @ android.os.asynctask$serialexecutor$1.run(asynctask.java:234)  @ java.util.concurrent.threadpoolexecutor.runworker(threadpoolexecutor.java:1113)  @ java.util.concurrent.threadpoolexecutor$worker.run(threadpoolexecutor.java:588)  @ java.lang.thread.run(thread.java:818) 

can tell me these errors mean?how can solve it?

ok got it. had change:

string login_url = "http://10.0.2.2/login.php";

to:

string login_url = "https://10.0.2.2/login.php";

Comments

Post a Comment

Popular posts from this blog

Hatching array of circles in AutoCAD using c# -

-
i beginner in autocad plugins .i have created array of circle using following code. now, have hatch circles in array .how that??how hatch circles @ once? moreover, how can return hatch method , use hatch objects.sorry language.thanks in advance. [assembly: commandclass(typeof(beamsection.class1))] namespace beamsection { public class class1 { //class1 obj = new class1(); [commandmethod("beamatsupport")] public void addlightweightpolyline() { // current document , database document acdoc = application.documentmanager.mdiactivedocument; database accurdb = acdoc.database; promptpointresult ppr = acdoc.editor.getpoint("\nselect starting point "); var ucs = acdoc.editor.currentusercoordinatesystem; point3d startingpt = ppr.value.transformby(ucs); list<double> radius = new list<double>(); radius.add(0.5);
Read more

ios - UITEXTFIELD InputView Uipicker not working in swift -

-
hello trying pop uipickerview view programmatically when user clicks on textfield. have tried doesn't doing anything. isn't working. nothing happening when click textfield class userprofiletableviewcontroller: uitableviewcontroller,uitextfielddelegate,uipickerviewdelegate,uipickerviewdatasource { var itempicker: uipickerview! = uipickerview() @iboutlet weak var gendertxtfield: uitextfield! var gender = ["male","female"] override func viewdidload() { super.viewdidload() gendertxtfield.delegate = self itempicker!.delegate = self itempicker!.datasource = self itempicker!.backgroundcolor = uicolor.blackcolor() self.gendertxtfield.inputview = itempicker } func numberofcomponentsinpickerview(pickerview: uipickerview) -> int{ return 1 } // returns # of rows in each component.. func pickerview(pickerview: uipickerview, numberofrowsincomponent component:
Read more

Python Pig Latin Translator -

-
so have been working on @ codecademy.com while trying learn python. don't know if blind , can't see why won't work or what. here's code won't let me use. function print variable if had typed in , print "empty" if didn't type anything. print "welcome english pig latin translator!" original = raw_input("what's name?") if len(original) > 0 print original else print "empty" if len(original) > 0 else the above lines contains syntax errors. try: if len(original) > 0: else: note added colons, ( : ).
Read more