awk - Find letters in columns which are same like in first column and print it -

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i have table values , have find match: first column others , print match.

input:

a:0  a:0.7541   a:0.7396    a:0.7694 a:0  0:0        0:0         0:0 c:0  c:0.8408   c:0.8459    c:0.7939 g:0  g:0.3415   g:0.3290    g:0.4228 g:0  g:0.0343   g:0.0378    t:8.237e06,g:0.02437 c:0 c:0.3895    c:0.3837    a:8.255e06,t:8.255e06,c:0.3623

output:

    a:0  0.7541     0.7396      0.7694     a:0  0          0           0     c:0  0.8408     0.8459      0.7939     g:0  0.3415     0.3290      0.4228     g:0  0.0343     0.0378      0.02437     c:0  0.3895     0.3837      0.3623

for last row.. if c in second column, print number after matching letter c in case, same columns, there more values separated ",". print number contain match letter c in case row. wrote :

awk '{split ($1,a,":");split ($2,b,":"); split($3,c,":"); split($4,d,":");       if(a[1]=b[1] && a[1]=c[1] && a[1]==d[1]) print $0}' /home/fil/desktop/uprava.txt

awk rescue!

$  awk '{key=substr($1,1,2);          n=split($nf,last,",");          if(n>1) for(i=1;i<=n;i++) if(last[i]~key) {$nf=last[i]; break}          for(i=2;i<=nf;i++) sub(key,"",$i);           print}' file | column -t  a:0  0.7541  0.7396  0.7694 a:0  0:0     0:0     0:0 c:0  0.8408  0.8459  0.7939 g:0  0.3415  0.3290  0.4228 g:0  0.0343  0.0378  0.02437 c:0  0.3895  0.3837  0.3623

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