c - Compiler doesn't show any errors or warnings but the program doesn't work -

i tried build , run following program, breaks down executing. thought maybe made mistake 0 errors , 0 warnings shown.

after researching such behavior on stackoverflow, saw misplaced semicolons or forgotten address-operators, not see in source code or overlooking something? c or gcc guru tell me wrong , why?

operating system windows 7, , compiler had enabled: -pedantic -w -wextra -wall -ansi

here source code:

#include <stdio.h> #include <string.h>  char *split(char * wort, char c) {     int = 0;     while (wort[i] != c && wort[i] != '\0') {         ++i;     }     if (wort[i] == c) {         wort[i] = '\0';         return &wort[i+1];     } else {         return null;     } }   int main() {     char *in = "some text here";     char *rest;     rest = split(in,' ');     if (rest == null) {         printf("\nstring not devided!");         return 1;     }     printf("\nerster teil: ");     puts(in);     printf("\nrest: ");     puts(rest);     return 0; } 

the expected behavior string "some text here" split @ first space ' ' , expected output be:

erster teil:  rest: text here 

you modifying string literal, that's undefined behavior. change this

char* in = "some text here"; 

to

char in[] = "some text here"; 

this makes in array , initializes "some text here". should use const prevent accidentally having bug when define pointer string literal.