unix - How can I omit a specific comma from my output? -

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i wanted format output using awk/sed, can't understand how it. using following command:

uptime | awk '{print $1" " $2" " $3$4" " $6" " $10$11$12}'  15:36:17 177days, 7 0.39,0.43,0.36

my desired output 

15:36:17 177days 7 0.39,0.43,0.36

i wanted omit first comma, i.e. 1 after "177days".

use either sub (substitute comma empty string) or substr (make substring last character):

uptime | awk '{sub(",","",$4); print $1" " $2" " $3$4" " $6" " $10$11$12}'  uptime | awk '{print $1" " $2" " $3 substr($4,1,length($4)-1) " " $6" " $10$11$12}'

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