sql server - How to select the 2 newest entries in a SQL database -

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i new sql , dont have knowledge on subject yet , have problem. trying select data database tables using query:

select  distinct     upper(m.name) 'member name',     m.memberid 'member id',     (b.booktitle + ' / ' + a.firstname + ' ' + a.lastname) 'title',     l.barcode 'barcode',     (convert(varchar(8), lr.duedate, 5) + ' renewed ' + convert(varchar(1),      (select count(lr.loanid)      loan l, loanrenewal lr      lr.loanid = l.loanid        , l.memberid = 's002')) + ' times') 'status',     bc.callnumber 'call number'      book b,     author a,     bookauthor ba,     bookcopy bc,     member m,     membertype mt,     loan l,     loanrenewal lr,     publishwork pw      m.memberid = 's002'     , m.memberid = l.memberid     , l.loanid = lr.loanid     , l.barcode = bc.barcode     , bc.isbn = pw.isbn     , pw.bookid = b.bookid     , ba.bookid = b.bookid     , b.main_authorid = a.authorid

when run this, result returns this

member name | member id | title                        | barcode | status                  | call number | lim hai mei | s002      | developing app / ben grimm| 1234567 | 20-02-16 renewed 4 times|tk5105.887 kar| lim hai mei | s002      | java 101 / yee chak thong    | abcdefg | 20-02-16 renewed 4 times|tk5105.886 kar| lim hai mei | s002      | java 101 / yee chak thong    | abcdefg | 25-02-16 renewed 4 times|tk5105.886 kar| lim hai mei | s002      | java 101 / yee chak thong    | abcdefg | 28-02-16 renewed 4 times|tk5105.886 kar|

but want return want recent records , how dynamically isolate data

 member name | member id | title                        | barcode | status                  | call number | lim hai mei | s002      | developing app / ben grimm| 1234567 | 20-02-16 renewed 1 times|tk5105.887 kar| lim hai mei | s002      | java 101 / yee chak thong    | abcdefg | 28-02-16 renewed 4 times|tk5105.886 kar|

please me not find suitable code dynamic , not in anyway hardcoding

you need use group & aggregation on column status(max recent one)

    select [member name],[member id],[title],[barcode],max(status),[call number]     (      --your code mentioned in question      )as     group [member name],[member id],[title],[barcode],[call number]

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