why can not run go function in go? -

this question has answer here:

this below code:

func main() {     values := []int{1, 2, 3, 4}     _, v := range values {         go func(x int) {             fmt.println(x)         }(v)     } }

if code have not go keyword, print 1, 2, 3, 4.

but can not print code now, why?

go version: 1.5.2 darwin/amd64

short: place wait @ end , print.
better option: communicate termination via channels.

long: go program lives long main goroutine lives.

when go somefunc(), it's not started immediately, somefunc() gets scheduled.

in case schedule goroutines , quit – , there's no reason scheduler run other goroutines.

JAV